Calculate the mass of silver formed by the interaction of an ammonia solution of silver oxide with 60 g of ethanal.

m (CH3C (= O) H) = 60 grams
m (Ag) -?
M (CH3CHO) = 44 grams / mol
n (CH3CHO) = m (CH3CHO) / M (CH3CHO)
n (CH3CHO) = 60 grams / 44 grams / mol = 1.36364 mol
M (Ag) = 108 grams / mol
CH3CHO + Ag2O = CH3COOH + 2Ag
From the stoichiometric coefficients of the reaction equation it follows that:
n (Ag) = 2n (CH3CHO) = 2 * 1.36364 mol = 2.72728 mol
m (Ag) = n (Ag) * M (Ag) = 2.72728 mol * 108 grams / mol = 294.55 grams
Answer: 294.55 grams