Calculate the mass of slaked lime that can be mined from limestone weighing 12 kg, if the mass fraction

Calculate the mass of slaked lime that can be mined from limestone weighing 12 kg, if the mass fraction of impurities in it is 10%. Determine the volume of carbon dioxide released during this.

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

The decomposition of 1 mol of limestone synthesizes 1 mol of calcium oxide and 1 mol of carbon monoxide.

Find the chemical amount of calcium carbonate. For this purpose, we divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 12,000 x 0.9 / 100 = 108 mol;

Let us determine the mass of 108 mol of calcium oxide.

To do this, multiply the amount of the substance by its molar weight.

M CaO = 40 + 16 = 56 grams / mol; m CaO = 108 x 56 = 6,048 grams;

Let’s calculate the volume of 108 mol of carbon dioxide.

To this end, we multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 108 x 22.4 = 2,419.2 liters;