Calculate the mass of slaked lime that can be obtained from 56 kg of CaO quicklime. In what state of aggregation

Calculate the mass of slaked lime that can be obtained from 56 kg of CaO quicklime. In what state of aggregation will Ca (OH) 2 be if we take: a) as much water as is required according to the reaction equation b) with an excess of water?

The reaction for the synthesis of slaked lime (calcium hydroxide) from unslaked lime (calcium oxide) is described by the following equation:

CaO + H2O = Ca (OH) 2;

During the reaction, 1 molecule of water is added to 1 molecule of calcium oxide.

Let’s calculate the chemical amount of a substance in 56 kilograms of calcium oxide.

To do this, divide the available weight of the oxide by the weight of one mole of oxide.

M CaO = 40 +16 = 56 grams / mol;

N CaO = 56,000 / 56 = 1000 mol;

The same amount of calcium hydroxide will be obtained. Let’s calculate its weight.

To do this, multiply the amount of hydroxide available by the weight of one mole of hydroxide.

M Ca (OH) 2 = 40 + (16 + 1) x 2 = 74 grams / mol;

m Ca (OH) 2 = 1000 x 74 = 74,000 grams = 74 kg;

If you take only the required amount of water, you will get a dry powder, if you take more water, you will get a solution.