Calculate the mass of slaked lime that can be obtained from 56 kg of CaO quicklime. In what state
Calculate the mass of slaked lime that can be obtained from 56 kg of CaO quicklime. In what state of aggregation will Ca (OH) 2 be, if we take: a) as much water as is required according to the reaction equation: b) with an excess of water?
First, we write down the reaction equation (to get slaked lime from quicklime, you need to add water):
CaO + H2O = Ca (OH) 2
Let’s find the amount of CaO by the formula N = m / M, where m is the mass of the substance, and M is the molar mass.
N = 56 / (40 + 16) = 1 (kmol)
Now we find the molar mass of Ca (OH) 2:
M = 40 + 2 x (16 + 1) = 40 + 34 = 74
The amount of CaO substance must be equal to the amount of Ca (OH) 2 substance, then the mass of the Ca (OH) 2 substance obtained is found by the formula:
m = M x N = 74 x 1 = 74 (kg)
a) with the amount of water required by the equation, Ca (OH) 2 will be in a solid state.
b) with an excess of water, the resulting substance will gradually dissolve in it.