Calculate the mass of sodium carbonate produced by passing 44.8 carbon dioxide through
September 3, 2021 | education
| Calculate the mass of sodium carbonate produced by passing 44.8 carbon dioxide through an excess of sodium hydroxide solution.
Given:
V (CO2) = 44.8 l
Find:
m (Na2CO3) -?
Solution:
CO2 + 2NaOH = Na2CO3 + H2O, – we solve the problem, relying on the composed reaction equation:
1) Find the amount of carbon dioxide that has reacted:
n (CO2) = V: Vm = 44.8 l: 22.4 l / mol = 2 mol
2) We compose a logical expression:
If 1 mol of CO2 gives 1 mol of Na2CO3,
then 2 mol of CO2 will give x mol of Na2CO3,
then x = 2 mol.
3) Find the mass of sodium carbonate formed during the reaction:
m (Na2CO3) = n * M = 2 mol * 106 g / mol = 212 g.
Answer: m (Na2CO3) = 212 g.
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