Calculate the mass of sodium carbonate produced by passing 44.8 carbon dioxide through

Calculate the mass of sodium carbonate produced by passing 44.8 carbon dioxide through an excess of sodium hydroxide solution.

Given:

V (CO2) = 44.8 l

Find:

m (Na2CO3) -?

Solution:

CO2 + 2NaOH = Na2CO3 + H2O, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of carbon dioxide that has reacted:

n (CO2) = V: Vm = 44.8 L: 22.4 L / mol = 2 mol

2) We compose a logical expression:

If 1 mol of CO2 gives 1 mol of Na2CO3,

then 2 mol of CO2 will give x mol of Na2CO3,

then x = 2 mol.

3) Find the mass of sodium carbonate formed during the reaction:

m (Na2CO3) = n * M = 2 mol * 106 g / mol = 212 g.

Answer: m (Na2CO3) = 212 g.