# Calculate the mass of sodium carbonate produced by passing 44.8 L of carbon dioxide through an excess

**Calculate the mass of sodium carbonate produced by passing 44.8 L of carbon dioxide through an excess of sodium hydroxide solution.**

When carbon dioxide is passed through an excess of sodium hydroxide solution, sodium carbonate is synthesized. The reaction is described by the following equation:

2NaOH + CO2 = Na2CO3 + H2O;

When 1 mol of gas is dissolved, 1 mol of soda is synthesized. Let’s calculate the amount of carbon dioxide available. To do this, we divide the volume of gas by the volume of 1 mole of gas. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N CO2 = 44.8 / 22.4 = 2 mol;

Let’s calculate the weight of this amount of soda. To do this, we multiply the amount of the substance by its molar weight.

M Na2CO3 = 23 x 2 + 12 + 16 x 3 = 106 grams / mol;

m Na2CO3 = 2 x 106 = 212 grams;