Calculate the mass of sodium chloride obtained with full use of 460 g of sodium.

The equation for the reaction of sodium with chlorine:

2 Na + Cl2 = 2 Na Cl.

From the reaction equation it follows that from 2 moles of sodium, 2 moles of sodium chloride are obtained.

Molar masses:

M (Na) = 23 g / mol;

M (Na Cl) = 23 + 35.5 = 58.5 g / mol.

Let’s solve the proportion: 23 – 58.5; 460 – x, whence x = 460 × 58.5 / 23 = 1170 g Na Cl.

Answer: 1170 g Na Cl.