Calculate the mass of sodium required to obtain 10.7 g of sodium chloride in an excess of chlorine, the reaction scheme: 2Na + Cl2 = 2NaCl
m (NaCl) = 10.7 g
m (Na) -?
2Na + Cl2 = 2NaCl, – we solve the problem, relying on the composed reaction equation:
1) Find the amount of sodium chloride obtained:
n (NaCl) = m: M = 10.7 g: 58.5 g / mol = 0.18 mol
2) We compose a logical expression:
If 2 mol Na gives 2 mol NaCl,
then x mol Na will give 0.18 mol NaCl,
then x = 0.18 mol.
3) Find the mass of sodium required for the full course of the reaction:
m (Na) = n * M = 0.18 mol * 23 g / mol = 4.14 g.
Answer: m (Na) = 4.14 g.
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