Calculate the mass of sodium sulfate, which is formed by the interaction of sodium hydroxide

Calculate the mass of sodium sulfate, which is formed by the interaction of sodium hydroxide with a mass of 1.6 grams with sulfuric acid.

Let’s implement the solution:

In accordance with the condition of the problem, we will write the data:
m = 1.6 g X g -?

2NaOH + H2SO4 = Na2SO4 + H2O – ion exchange, sodium sulfate is released.

We make calculations:
M (NaOH) = 39.9 g / mol;

M (Na2SO4) = 141.8 g / mol;

Y (NaOH) = m / M = 1.6 / 39.9 = 0.04 mol.

Proportion:
0.04 mol (NaOH) – X mol (Na2SO4);

-2 mol -1 mol hence, X mol (Na2SO4) = 0.04 * 1/2 = 0.02 mol.

Find the mass of the product:
m (Na2SO4) = Y * M = 0.02 * 141.8 = 2.84 g

Answer: the mass of sodium sulfate is 2.84 g