1. Let’s write the equation of interaction of sodium with glycerin:
2CH2 (OH) CH (OH) CH2 (OH) + 6Na → 2CH2 (ONa) CH (ONa) CH2 (ONa) + 3H2 ↑;
2.Calculate the chemical amount of glycerin:
n (glycerol) = m (glycerol): M (glycerol);
M (CH2 (OH) CH (OH) CH2 (OH)) = 12 + 2 + 17 + 13 + 17 + 14 + 17 = 92 g / mol;
n (glycerol) = 3.6: 92 = 0.0391 mol;
3. Determine the amount of sodium entering into the reaction:
n (Na) = n (glycerol) * 3 = 0.0392 * 3 = 0.1176 mol;
4.calculate the mass of sodium:
m (Na) = n (Na) * M (Na) = 0.1176 * 23 = 2.7 g.
Answer: 2.7 g.
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