Calculate the mass of sucrose that underwent hydrolysis, taking into account the fact that ethyl alcohol

| September 12, 2021 | education

Calculate the mass of sucrose that underwent hydrolysis, taking into account the fact that ethyl alcohol with a mass of 46 g was obtained from the resulting glucose.

Let’s find the amount of ethanol substance by the formula:

n = m: M.

M (C2H5OH) = 46 g / mol.

n = 46 g: 46 g / mol = 1 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

С6Н12О6 → 2С2Н5ОН + 2СО2 ↑.

According to the reaction equation, there is 1 mole of glucose per 2 mol of ethanol. Substances are in quantitative ratios of 2: 1.

The amount of glucose substance will be 2 times less than that of alcohol.

n (C6H12O6) = ½ n (C2H5OH) = 1: 2 = 0.5 mol.

Let’s compose the equation of the sucrose hydrolysis reaction. The reaction products are 1 mole of glucose and 1 mole of fructose.

C12H22O11 + HOH → C6H12O6 + C6H12O6.

Glucose and sucrose are in quantitative ratios of 1: 1.

The amount of substance will be equal.

n (C6H12O6) = n (C6H12O6) = 0.5 mol.

Let’s find the mass of sucrose.

M (C12H12O11) = 332 g / mol.

m = n × M.

m = 332 g / mol × 0.5 mol = 166 g.

Answer: 166 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.