Calculate the mass of sulfur oxide (4) formed during the combustion of 40 tons of sulfur if the yield

Calculate the mass of sulfur oxide (4) formed during the combustion of 40 tons of sulfur if the yield of the reaction product is 85%.

The oxidation reaction of sulfur with oxygen is described by the following chemical reaction equation:

S + O2 = SO2;

1 mole of gas reacts with 1 mole of sulfur. 1 mol of its oxide is synthesized.

Let’s calculate the available chemical amount of sulfur.

M S = 32 grams / mol;

N S = 40,000,000/32 = 1,250,000 mol;

Taking into account the reaction yield of 85%, 1,250,000 x 0.85 = 1,062,500 mol of sulfur oxide will be synthesized.

Let’s calculate its weight.

M SO2 = 32 + 16 x 2 = 64 grams / mol;

m SO2 = 1,062,500 x 64 = 68 tons;