Calculate the mass of sulfur oxide that is formed in the reaction of 30 g of copper with a concentration

Calculate the mass of sulfur oxide that is formed in the reaction of 30 g of copper with a concentration of sulfuric acid if the reaction yield is 70%.

Let’s find the amount of substance Cu:

M (Cu) = 64 g / mol.

n = 30 g: 64 g / mol = 0.47 mol.

Let’s find the quantitative ratios of substances.

Cu + 2H2SO4 = CuSO4 + SO2 + 2H2O.

For 1 mol of Cu, there is 1 mol of SO2.

Substances are in quantitative ratios 1: 1.

Amount of substance

n (Cu) = n (SO2) = 0.47 mol.

Let’s find the mass of SO2.

M (SO2) = 64 g / mol.

m = n × M.

m = 64 g / mol × 0.47 mol = 30.08 g.

30.08 g – 100%, (according to theory, received);

X g – 70%, (according to the condition of the problem).

X = (70% × 30.08): 100% = 21.056 g.

Answer: 21.056 g.