Calculate the mass of sulfur that will be required for the reaction of 2.7 g of aluminum.

1. The reaction of aluminum with sulfur reflects the equation:

2Al + 3S = Al2S3;

2. Let’s calculate the chemical amount of aluminum:

n (Al) = m (Al): M (Al) = 2.7: 27 = 0.1 mol;

3. Determine the amount of reacted sulfur:

n (S) = n (Al) * 3: 2 = 0.1 * 3: 2 = 0.15 mol;

4. Let’s calculate the mass of sulfur:

m (S) = n (S) * M (S) = 0.15 * 32 = 4.8 g.

Answer: 4.8 g.