Calculate the mass of sulfuric acid (H₂SO₄) that will be required to neutralize 100 g of 10% NaOH alkali solution.

| March 4, 2021 | education

Let’s find the mass of alkali by the formula:

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (100 g × 10%): 100% = 10 g.

Or:

100 g – 100%,

X g – 10%,

X = (100 g × 10%): 100% = 10 g.

Let’s find the amount of sodium hydroxide substance by the formula: n = m: M.

M (NaOH) = 23 + 16 + 1 = 40 g / mol.

n = 10 g: 40 g / mol = 0.25 mol.

Let’s compose the equation of the reaction between sulfuric acid and alkali. Let’s find the quantitative ratios of substances.

H2SO4 + 2NaOH = Na2SO4 + 2H2O.

There are 2 moles of alkali per mole of acid. Substances are found in quantitative ratios of 1: 2. The amount of acid substance will be 2 times less than alkali.

1/2 n (H2SO4) = n (NaOH) = 0.25: 2 = 0.125 mol.

m = n × M,

M (H2SO4) = 98 g / mol.

m = 0.125 mol × 98 g / mol = 12.25 g.

Answer: 12.25 g.



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