Calculate the mass of sulfuric acid obtained by dissolving 100 liters of sulfur oxide 6 in water.

Given:
V (SO3) = 100l
Find: m (H2SO4) -?
Decision:
Reaction equation: SO3 + H2O = H2SO4
n (nu) (SO3) = V / Vm = 100l / 22.4l / mol = 4.46mol
n (SO3) = n (H2SO4) = 4.46 mol
m (H2SO4) = n * M = 4.46 mol * 98g / mol = 437.08g



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