Calculate the mass of sulfuric acid required to neutralize a solution containing 10 g of sodium hydroxide.

Let’s write down the reaction scheme and arrange the coefficients:
2NaOH + H2SO4 = Na2SO4 + 2H2O
From the reaction equation it can be seen that in order to neutralize 2 mol of NaOH, 1 mol of H2SO4 is required.
Determine the amount of substance n (NaOH) = m (NaOH) / M (NaOH), where:
m (NaOH) – mass of NaOH, M (NaOH) – molar mass of NaOH, M (NaOH) = 40 g / mol
n (NaOH) = 10/40 = 0.25 mol.
It turns out that the amount of sulfuric acid substance:
n (H2SO4) = n (NaOH) / 2 = 0.25 / 2 = 0.125 mol.
M (H2SO4) = 98 g / mol is the molar mass of sulfuric acid.
Determine the mass of sulfuric acid:
m (H2SO4) = n (H2SO4) * M (H2SO4) = 0.125 * 98 = 12.25 g