Calculate the mass of sulfuric acid required to obtain 284 grams of sodium sulfate.

Find the amount of sodium sulfate substance by the formula:

n = m: M.

M (Na2SO4) = 23 × 2 + 32 + 16 × 4 = 142 g / mol.

n = 284 g: 142 g / mol = 2 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

2NaOH + H2SO4 = Na2SO4 + 2H2O.

According to the reaction equation, 1 mol of sodium sulfate accounts for 1 mol of sulfuric acid. The substances will be equal.

n (H2SO4) = n (Na2SO4) = 2 mol.

Let’s find the mass of sulfuric acid by the formula:

m = n × M,

M (H2SO4) = 98 g / mol.

m = 2 mol × 98 g / mol = 196 g.

Answer: 196