Calculate the mass of sulfuric acid required to react with an 8g portion of magnesium oxide.

Calculate the mass of sulfuric acid required to react with an 8g portion of magnesium oxide. Calculate the mass of the salt formed.

1. Let’s compose the reaction equation:

MgO + H2SO4 = MgSO4 + H2 ↑;

2.Calculate the chemical amount of magnesium oxide:

n (MgO) = m (MgO): M (MgO);

M (MgO) = 24 + 16 = 40 g / mol;

n (MgO) = 8: 40 = 0.2 mol;

3. Determine the amount and find the mass of sulfuric acid:

n (H2SO4) = n (MgO) = 0.2 mol;

m (H2SO4) = n (H2SO4) * M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

m (H2SO4) = 0.2 * 98 = 19.6 g;

4.Calculate the amount and weight of magnesium sulfate:

n (MgSO4) = n (MgO) = 0.2 mol;

m (MgSO4) = n (MgSO4) * M (MgSO4);

M (MgSO4) = 24 + 32 + 4 * 16 = 120 g / mol;

m (MgSO4) = 0.2 * 120 = 24 g.

Answer: 19.6 g H2SO4, 24 g MgSO4.