Calculate the mass of sulfuric acid that is required to neutralize a solution containing 10 mol of sodium hydroxide.

Given:
n (NaOH) = 10 mol

To find:
m (H2SO4) -?

Decision:
1) H2SO4 + 2NaOH => Na2SO4 + 2H2O;
2) n (H2SO4) = n (NaOH) * 2 = 10 * 2 = 20 mol;
3) m (H2SO4) = n (H2SO4) * M (H2SO4) = 20 * 98 = 1960

Answer: The mass of H2SO4 is 1960.



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