Calculate the mass of sulfuric acid that reacts with 5.6 g of potassium hydroxide. Find the number of water molecules.

Given:
m (KOH) = 5.6 g
To find:
m (H2SO4)
N (H20)
Decision:
2KOH + H2SO4 = K2SO4 + 2H2O
n (KOH) = 5.6 / 56 = 0.1 mol
n (KOH): n (H20) = 2: 2
n (H20) = 0.1 mol
N (H2O) = 0.1 * 6.02 * 10 ^ 23 = 6.02 * 10 ^ 22
n (H2O): n (H2SO4) = 2: 1
n (H2SO4) = 0.1 / 2 = 0.05 mol
m (H2SO4) = 0.05 * 98 = 4.9 g
Answer: 4.9 g; 6.02 * 10 ^ 22