Calculate the mass of sulfuric acid that reacts with 5.6 g of potassium hydroxide to form potassium sulfate and water.

1. The reaction proceeds according to the equation:

H2SO4 + 2KOH = K2SO4 + 2H2O;

2.Calculate the chemical amount of potassium hydroxide:

n (KOH) = m (KOH): M (KOH);

M (KOH) = 39 + 16 + 1 = 56 g / mol;

n (KOH) = 5.6: 56 = 0.1 mol;

3.Comparing the stoichiometric coefficients in the reaction equation, we find the amount of sulfuric acid:

n (H2SO4) = n (KOH): 2 = 0.1: 2 = 0.05 mol;

4. find the mass of the reacting sulfuric acid:

m (H2SO4) = n (H2SO4) * M (H2SO4);

M (H2SO4) = 2 + 32 + 16 * 4 = 98 g / mol;

m (H2SO4) = 0.05 * 98 = 4.9 g.

Answer: 4.9 g.