Calculate the mass of sulfuric acid, which is formed by the interaction of sulfur (IV) oxide with 180 gr. water.

Let’s implement the solution:
1. By the condition of the problem, it is known:
m = 180 g. X g. -?
SO3 + H2O = H2SO4 – compounds, sulfuric acid was obtained;
1 mol 1 mol.
2. Calculation:
M (H2O) = 18 g / mol;
M (H2SO4) = 98 g / mol.
3. Determine the amount of the original substance, if the mass is known:
Y (H2O) = m / M = 180/18 = 10 mol;
Y (H2SO4) = 10 mol since the amount of these substances according to the equation is 1 mol.
4. Find the mass of acid:
m (H2SO4) = Y * M = 10 * 98 = 980 g.
Answer: sulfuric acid with a mass of 980 g was formed.

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