Calculate the mass of table salt (in g) and the volume of water (in ml) required to prepare 300 g

Calculate the mass of table salt (in g) and the volume of water (in ml) required to prepare 300 g of a 5% solution of this salt.

Given:
m solution (NaCl) = 300 g
ω (NaCl) = 5%

To find:
m (NaCl) -?
V (H2O) -?

Solution:
1) m (NaCl) = ω * m solution / 100% = 5% * 300/100% = 15 g;
2) m (H2O) = m solution (NaCl) – m (NaCl) = 300 – 15 = 285 g;
3) V (H2O) = m (H2O) * ρ (H2O) = 285 * 1 = 285 ml.

Answer: The mass of NaCl is 15 g; H2O volume – 285 ml.