Calculate the mass of the acid obtained by heating 55 g of a 40% ethanal solution with an excess

| April 30, 2021 | education

Calculate the mass of the acid obtained by heating 55 g of a 40% ethanal solution with an excess of copper (II) hydroxide.

СН3 –СОН + 2 Сu (ОН) 2 → H3C- COOH + 2 CuOH + H2O.

Find the mass of ethanal in solution by the formula:

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (100 g × 10%): 100% = 10 g.

m (substance) = (55 g × 40%): 100% = 22 g.

Find the amount of ethanal substance by the formula n = m: M

М (СН3 –СОН) = 12 + 12 + 16 + 4 = 44 g / mol.

n = 22 g: 44 g / mol = 0.5 mol.

According to the reaction equation, 1 mol of ethanal accounts for 1 mol of acetic acid. The substances are in quantitative ratios of 1: 1. The amount of ethanal substance and acid will be the same.

n (СН3 –СОН) = n (СН3 –СООН) = 0.5 mol.

Find the mass of acetic acid using the formula.

m = n × M,

M (CH3 –COOH) = 60 g / mol.

m = 60 g / mol × 0.5 mol = 30 g.



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