Calculate the mass of the ester that is formed by the reaction of 150 g of acetic acid

Calculate the mass of the ester that is formed by the reaction of 150 g of acetic acid with ethanol if the product yield is 80%.

Solution:
1. In accordance with the condition of the problem, we compose the equation:
CH3COOH + C2H5OH = CP3COO – C2H5 + H2O – esterification reaction, ethyl acetate is formed;
2. Calculation of the molar masses of substances:
M (CH3COOH) = 60 g / mol;
M (ether) = 88 g / mol.
3. Determine the amount of mol of acetic acid:
Y (CH3COOH) = m / M = 150/60 = 2.5 mol;
Y (ether) = 2.5 mol, since the amount of these substances according to the equation is 1 mol.
4. Find the mass of the ether:
m (ether) = Y * M = 2.5 * 88 = 220 g.
Answer: The mass of the ester is 220 g.