Calculate the mass of the ester that will result from the interaction of 6.4 g

| March 17, 2021 | education

Calculate the mass of the ester that will result from the interaction of 6.4 g of methyl alcohol with 7.5 g of 80% acetic acid solution. the ether yield was 75%.

1. Let us write down the equation for obtaining methyl acetate:

CH3COOH + CH3OH → CH3COOCH3 + H2O;

2.Calculate the mass of acetic acid:

m (CH3COOH) = w (CH3COOH) * m (solution) = 0.8 * 7.5 = 6 g;

3. find the chemical amounts of acid and alcohol:

n (CH3COOH) = m (CH3COOH): M (CH3COOH);

M (CH3COOH) = 12 + 3 + 12 + 32 + 1 = 60 g / mol;

n (CH3COOH) = 6: 60 = 0.1 mol;

n (CH3OH) = m (CH3OH): M (CH3OH);

M (CH3OH) = 12 + 3 + 17 = 32 g / mol;

n (CH3OH) = 6.4: 32 = 0.2 mol;

4. by the amount of acid, since it is in short supply, we determine the theoretical amount of ester:

ntheor (CH3COOCH3) = n (CH3COOH) = 0.1 mol;

5.Calculate the theoretical mass of the ether:

mtheor (CH3COOCH3) = ntheor (CH3COOCH3) * M (CH3COOCH3);

M (CH3COOCH3) = 12 + 3 + 12 + 32 + 12 + 3 = 74 g / mol;

mtheor (CH3COOCH3) = 0.1 * 74 = 7.4 g;

6.Calculate the practical mass of methyl acetate:

mpractice (CH3COOCH3) = mtheor (CH3COOCH3) * ν = 7.4 * 0.75 = 5.55 g.

Answer: 5.55 g.



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