Calculate the mass of the ester, which is formed as a result of the reaction of 32 g of acetic acid

Calculate the mass of the ester, which is formed as a result of the reaction of 32 g of acetic acid with 56 g of ethyl alcohol, if the mass fraction of the ester yield is 55%.

Reaction of acetic acid with ethyl alcohol:
CH3COOH + C2H5OH = CH3COOCH2CH3 + H2O
We count the amount of reacted substances:
n (CH3COOH) = 32/60 = 0.533 mol
n (C2H5OH) = 56/46 = 1.217 mol
Because ethyl alcohol reacted in excess, the output is 0.533 mol of ether
m (CH3COOCH2CH3) = 0.533 * 88 = 46.9 g
But since the mass fraction of only 55% of the pure substance is obtained less:
m (CH3COOCH2CH3) = 46.9 * 55/100 = 25.8 g
The mass of the formed ether is 25.8 g