Calculate the mass of the formed copper if copper (II) oxide with a mass of 64 g reacts with hydrogen.

Copper oxide is reduced with hydrogen gas. This synthesizes metallic copper and water. This reaction is described by the following equation:

CuO + H2 = Cu + H2O;

Copper oxide reacts with hydrogen in equal molar amounts. At the same time, the same equal amounts of copper and water are synthesized.

Let’s calculate the chemical amount of copper oxide.

To do this, divide the weight of the oxide by the weight of 1 mole of oxide.

M CuO = 64 + 16 = 80 grams / mol; N CuO = 64/80 = 0.8 mol;

Thus, it is possible to carry out the reduction of 0.8 mol of copper oxide and synthesize 0.8 mol of copper.

Its weight will be:

M Cu = 64 grams / mol; m Cu = 64 x 0.8 = 51.2 grams;