Calculate the mass of the metal obtained by reduction with carbon monoxide (II) from iron (III) oxide with a mass of 32 g.

Given:

m (Fe2O3) = 32 g;

To find:

m (Fe) -?

Solution:

1) We compose the reaction equation corresponding to the condition of the problem:

Fe2O3 + 3CO = Fe + 3CO2

2) Find the amount of ferric oxide contained in 32 grams of oxide:

n (Fe2O3) = m: M = 32 g: 160 g / mol = 0.2 mol;

3) We compose a logical expression:

if 1 mol of Fe2O3 gives 1 mol of Fe,

then 0.2 mol of Fe2O3 will give x mol of Fe,

then x = 0.2 mol.

4) Find the mass of iron released during the reaction:

m (Fe) = n * M = 0.2 mol * 56 g / mol = 11.2 g.

Answer: m (Fe) = 11.2 g.