Calculate the mass of the nitric acid solution (the mass fraction of HNO3 in it is 14%) required for the reaction with 2 mol of sodium carbonate.
1. Let’s make a chemical equation, not forgetting to put down the coefficients:
Na2CO3 + 2HNO3 = 2NaNO3 + CO2 + H2O.
2. Let’s make the proportion:
Na2CO3 / HNO3 = 1/2; hence:
n (HNO3) = 4 mol.
3. Find the mass of HNO3:
m (HNO3) = n * M = 4 * 63 = 252g.
4.m (solution) = 252 / 0.14 = 1800g.
Answer: m (HNO3 solution) = 1800g.
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