Calculate the mass of the Oxide, which reacts with 11.2 grams to form Fe2O3.

Given:
m (Fe) = 11.2 g

To find:
m (Fe2O3) -?

1) Write the reaction equation:
4Fe + 3O2 => 2Fe2O3;
2) Determine the molar mass of Fe:
M (Fe) = Ar (Fe) = 56 g / mol;
3) Calculate the amount of the substance Fe:
n (Fe) = m (Fe) / M (Fe) = 11.2 / 56 = 0.2 mol;
4) Determine the amount of the substance Fe2O3:
n (Fe2O3) = n (Fe) * 2/4 = 0.2 * 2/4 = 0.1 mol;
5) Calculate the molar mass of Fe2O3:
M (Fe2O3) = Mr (Fe2O3) = Ar (Fe) * N (Fe) + Ar (O) * N (O) = 56 * 2 + 16 * 3 = 160 g / mol;
6) Calculate the mass of Fe2O3:
m (Fe2O3) = n (Fe2O3) * M (Fe2O3) = 0.1 * 160 = 16 g.

Answer: The mass of Fe2O3 is 16 g.