Calculate the mass of the potassium salt of aminoacetic acid, which is formed by the interaction of 5.85 g

| June 17, 2021 | education

Calculate the mass of the potassium salt of aminoacetic acid, which is formed by the interaction of 5.85 g of potassium hydroxide with 10 g of aminoacetic acid.

Let’s find the amount of aminoacetic acid substance by the formula:

n = m: M.

M (CH2 (NH2) COOH) = 75 g / mol.

n = 10 g: 75 g / mol = 0.133 mol.

Let’s find the amount of the substance KOH.

n = m: M.

M (KOH) = 46 g / mol.

n = 5.85 g: 46 g / mol 0.1 mol.

KOH is given in disadvantage.

Let’s compose the reaction equation, find the quantitative ratios of substances.

CH2 (NH2) COOH + KOH = CH2 (NH2) COOK + H2O.

According to the reaction equation, there is 1 mol of salt for 1 mol of KOH. The substances are in quantitative ratios of 1: 1.

The amount of substance will be equal.

n (KOH) = n (CH2 (NH2) COOK) = 0.1 mol.

Find the mass of CH2 (NH2) COOK.

M (CH2 (NH2) COOK) = 113 g / mol.

m = n × M.

m = 113 g / mol 0.1 mol = 11.3 g.

Answer: 11.3 g.



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