Calculate the mass of the precipitate formed by merging the aluminum nitrate solution

| September 3, 2021 | education

Calculate the mass of the precipitate formed by merging the aluminum nitrate solution and the solution containing 160 g of sodium hydroxide.

Let’s write the reaction equation, not forgetting to equalize it (usually, when arranging the coefficients, the main thing for us is that the amount of oxygen in the left and right sides of the equation coincides):

Al (NO3) 3 + 3NaOH = 3NaNO3 + Al (OH) 3;

Now, based on the mass of NaOH given to us, we find its number mol (n):

n (NaOH) = m (NaOH): M (NaOH) = 160 g: 40 g / mol = 4 mol.

Taking into account the coefficient in front of NaOH, the number of moles of Al (OH) 3 (after all, it is he who precipitates) will be 3 times less, that is: n (Al (OH) 3) = 4 mol: 3 = 1.3 mol (when rounding ).

m (Al (OH) 3) = n (Al (OH) 3) * M (Al (OH) 3) = 1.3 mol * 78 g / mol = 101.4 g.



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