Calculate the mass of the precipitate formed by the interaction of 3.25 g of calcium chloride with an excess of sodium phosphate

| November 26, 2020 | education

Calculate the mass of the precipitate formed by the interaction of 3.25 g of calcium chloride with an excess of sodium phosphate. how much sodium phosphate will be consumed? Calculate its mass.

Let’s write the reaction equation:
3CaCl2 + 2Na3PO4 = Ca3 (PO4) 2 (precipitate) + 6NaCl
Let’s calculate the amount of CaCl2
n (CaCl2) = m / M = 3.25g / 111g / mol = 0.03 mol
Find the Ratio of Na3PO4 and potassium chloride by the reaction equation
n (Na3PO4): n (CaCl2) = 2: 3, which means the amount of substance Na3PO4 = 2 x 3 / 0.03 = 0.02 mol
m (Na3PO4) = n x M = 0.02 mol x 141 g / mol = 2.82 g
The ratio of the resulting precipitate to calcium chloride
n (Ca3 (PO4) 2): n (CaCl2) = 1: 3, which means the amount of sediment substance = 1 x 0.03 / 3 = 0.01 mol
sediment weight
m (Ca3 (PO4) 2) = n xM = 0.01 mol х 310 g / mol = 3.1 g



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