Calculate the mass of the precipitate formed by the interaction of hydrogen sulfide with copper sulfate, weighing 80 g.

Decision:
Let’s write the reaction equation:
H2S + CuSO4 = CuS + H2SO4 – exchange reaction, precipitate of copper sulfide is released;
Determine the molar mass:
M (CuSO4) = 64 + 32 + 64 = 160 g / mol;
M (CuS) = 64 + 32 = 96 g / mol;
Let’s make calculations: Y (CuSO4) = m (CuSO4) / M (CuSO4);
Y (CuSO4) = 80/160 = 0.5 mol;
Determine the mass of copper sulfide:
Y (CuS) = m (CuS) / M (CuS); Y (CuS) = 0.5 * 96 = 48 g.
Answer: the mass of copper sulfide sediment is 48 g.