Calculate the mass of the precipitate formed by the interaction of sodium hydroxide 4 g with a solution

| August 7, 2021 | education

Calculate the mass of the precipitate formed by the interaction of sodium hydroxide 4 g with a solution of ferric chloride (3)

1.Let’s find the amount of ferric chloride substance by the formula:

n = m: M.

M (FeCl3) = 56 + 105 = 161 g / mol.

n = 4 g: 161 g / mol = 0.02 mol.

2. Let’s compose the equation of the reaction between sodium hydroxide and ferric chloride. Let’s determine in what quantitative ratios they are.

3NaOH + FeCl3 = 3NaCl + Fe (OH) 3 ↓.

For 1 mol of iron chloride, there is 1 mol of iron (III) hydroxide (precipitates). The substances are in quantitative ratios of 1: 1. The amount of the substance will be the same.

n (Fe (OH) 3) = n (FeCl3) = 0.02 mol.

3.Let’s find the mass of iron hydroxide by the formula:

m = n × M,

M (Fe (OH) 3) = 56 + 3 (16 + 1) = 107 g / mol.

m = 0.02 mol × 107 g / mol = 2.14 g.

Answer: 2.14g.



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