Calculate the mass of the precipitate formed by the interaction of solutions containing, respectively

Calculate the mass of the precipitate formed by the interaction of solutions containing, respectively, barium nitrate with a mass of 26.1 g and sulfuric acid with a mass of 4.5 g.

The reaction between sulfuric acid and barium nitrate is described by the following chemical reaction equation:

Ba (NO3) 2 + H2SO4 = BaSO4 + 2HNO3;

When 1 mol of barium nitrate and 1 mol of sodium sulfuric acid interact, 1 mol of insoluble barium sulfate is synthesized.

Let’s calculate the chemical amount of a substance that is contained in 4.5 grams of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 4.5 / 98 = 0.046 mol;

Let’s calculate the chemical amount of a substance that is contained in 26.1 grams of barium nitrate.

M Ba (NO3) 2 = 137 + (14 + 16 x 3) x 2 = 261 grams / mol;

N Ba (NO3) 2 = 26.1 / 261 = 0.1 mol;

Thus, not more than 0.046 mol of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

m BaSO4 = 233 x 0.046 = 10.72 grams;