Calculate the mass of the precipitate formed by the interaction of two solutions

Calculate the mass of the precipitate formed by the interaction of two solutions, one of which contains 21.2 g of sodium carbonate, and the other contains calcium chloride.

1. Let’s write down the reaction of ion exchange:

Na2CO3 + CaCl2 = CaCO3 ↓ + 2NaCl;

2.Calculate the chemical amount of sodium carbonate:

n (Na2CO3) = m (Na2CO3): M (Na2CO3);

M (Na2CO3) = 2 * 23 + 12 + 3 * 16 = 106 g / mol;

n (Na2CO3) = 21.2: 106 = 0.2 mol;

3. Determine the amount and calculate the mass of calcium carbonate:

n (CaCO3) = n (Na2CO3) = 0.2 mol;

m (CaCO3) = n (CaCO3) * M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

m (CaCO3) = 0.2 * 100 = 20 g.

Answer: 20 g.