Calculate the mass of the precipitate formed by the interactions of ferric chloride three

Calculate the mass of the precipitate formed by the interactions of ferric chloride three and 1230 g of 70% sodium hydroxide solution.

Given:

m (NaOH) = 1230 g

w% (NaOH) = 70%

To find:

m (draft) -?

Decision:

FeCl3 + 3NaOH = Fe (OH) 3 + 3NaCl, – we solve the problem using the composed reaction equation:

1) Find the mass of sodium hydroxide in the solution:

m (NaOH) = 1230 g * 0.7 = 861 g

2) Find the amount of sodium hydroxide:

n (NaOH) = 861 g: 40 g / mol = 21.525 mol

3) We compose a logical expression:

if 3 mol of NaOH gives 1 mol of Fe (OH) 3,

then 21.525 mol of NaOH will give x mol of Fe (OH) 3,

then x = 7.175 mol.

4) Find the mass of iron hydroxide precipitated as a result of the reaction:

m (Fe (OH) 3) = n * M = 7.175 mol * 107 g / mol = 767.725 g.

Answer: m (Fe (OH) 3) = 767.725 g.