Calculate the mass of the precipitate formed when draining 200 g of a 12.25% sulfuric acid solution with a solution of barium chloride.

To start the task, let’s write the exchange reaction equation:
BaCl2 + H2SO4 = BaSO4 + 2HCl
The interaction of barium cations (Ba (2+)) and sulfo group anions (SO3 (2-)) is a qualitative reaction for the barium ion.
The solution becomes cloudy, like milk. The phenomenon is explained by the production of finely dispersed insoluble barium sulfate.
Let’s find exactly how much pure barium chloride we have:
m = 200 grams * 0.1225 = 24.5 grams
Now you need to make a proportion to find the mass of barium sulfate:
24.5 – x
98 – 233
Whence x = 24.5 * 233/98 = 58.25 grams.