Calculate the mass of the precipitate obtained by the action of a solution containing 9.8 g of sulfuric
Calculate the mass of the precipitate obtained by the action of a solution containing 9.8 g of sulfuric acid with a solution of barium chloride.
Barium chloride reacts with sulfuric acid. This results in the formation of water-insoluble barium sulfate, which precipitates. This reaction is described by the following chemical equation.
BaCl2 + H2SO4 = BaSO4 + 2HCl;
Barium chloride reacts with sulfuric acid in equivalent molar amounts. In this case, an equal amount of insoluble salt is synthesized.
Let’s find the chemical amount of sulfuric acid.
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 9.8 / 98 = 0.1 mol;
The same amount of barium sulfate will be synthesized.
Let’s determine its weight.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.1 x 233 = 23.3 grams;