Calculate the mass of the precipitate obtained by the interaction of 49 g of sulfuric acid with barium hydroxide.

The reaction of interaction of sulfuric acid with barium hydroxide is described by the following chemical reaction equation:

Ba (OH) 2 + H2SO4 = BaSO4 + 2H2O;

Upon the interaction of 1 mol of barium hydroxide and 1 mol of sulfuric acid, 1 mol of insoluble barium sulfate is synthesized.

Let’s calculate the chemical amount of a substance that is contained in 49 grams of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 49/98 = 0.5 mol;

The same amount of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

m BaSO4 = 233 x 0.5 = 116.5 grams;