Calculate the mass of the precipitate that formed during the interaction

Calculate the mass of the precipitate that formed during the interaction of 2 solutions, the first containing 35.5 g of sodium sulfate, and the second barium nitrate.

The reaction between sodium sulfate and barium chloride is described by the following chemical reaction equation:

BaCl2 + Na2SO4 = BaSO4 + 2NaCl;

When 1 mol of barium chloride and 1 mol of sodium sulfate interact, 1 mol of insoluble barium sulfate is synthesized.

Let’s calculate the chemical amount of a substance that is contained in 35.5 grams of sodium sulfate.

M Na2SO4 = 23 x 2 + 32 + 16 x 4 = 142 grams / mol;

N Na2SO4 = 35.5 / 142 = 0.25 mol;

The same amount of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

m BaSO4 = 233 x 0.25 = 58.25 grams;