Calculate the mass of the precipitate that formed when mixing a solution containing 34 g

Calculate the mass of the precipitate that formed when mixing a solution containing 34 g of silver nitrate and an excess of barium chloride solution.

1. Let’s compose the equation of the ongoing reaction of ion exchange:
2AgNO3 + BaCl2 = 2AgCl ↓ + Ba (NO3) 2;
2.Calculate the chemical amount of silver nitrate:
n (AgNO3) = m (AgNO3) * M (AgNO3);
M (AgNO3) = 108 + 14 + 3 * 16 = 170 g / mol;
n (AgNO3) = 34: 170 = 0.2 mol;
3. Determine the amount of the formed silver chloride and calculate its mass:
n (AgCl) = n (AgNO3) = 0.2 mol;
m (AgCl) = n (AgCl) * M (AgCl);
M (AgCl) = 108 + 35.5 = 143.5 g / mol;
m (AgCl) = 0.2 * 143.5 = 28.7 g.
Answer: 28.7 g.