Calculate the mass of the precipitate that forms when 146 g of hydrochloric acid reacts with silver nitrate.

univerkov | January 17, 2021 | education

Given:
m (HCl) = 146 g
To find:
m (AgCl)
Decision:
HCl + AgNO3 = AgCl + HNO3
n (HCl) = m / M = 146 g / 36.5 g / mol = 4 mol
n (HCl): n (AlCl) = 1: 1
n (AlCl) = 4 mol
m (AgCl) = n * M = 4 mol * 143.5 g / mol = 574 g
Answer: 574 g

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.