Calculate the mass of the precipitate that forms when 3.2 g of sulfur dioxide is passed

Calculate the mass of the precipitate that forms when 3.2 g of sulfur dioxide is passed through a barium hydroxide solution.

Sulfur dioxide react with barium hydroxide to form an insoluble precipitate. The chemical reaction is described by the following equation:

Ba (OH) 2 + SO2 = BaSO3 ↓ + H2O;

Let’s find the amount of the substance contained in 3.2 grams of sulfur dioxide.

M SO2 = 32 + 16 x 2 = 64 grams / mol;

N SO2 = 3.2 / 64 = 0.05 mol;

Let’s find the mass of insoluble salt.

Its molar mass is:

M BaSO3 = 137 + 32 + 16 x 3 = 217 grams / mol;

The mass of insoluble salt will be:

m BaSO3 = 217 x 0.05 = 10.85 grams;