Calculate the mass of the precipitate that forms when a 5% solution weighing 200 g of sulfuric
Calculate the mass of the precipitate that forms when a 5% solution weighing 200 g of sulfuric acid interacts with barium chloride.
The reaction between sulfuric acid and barium chloride is described by the following chemical reaction equation:
BaCl2 + H2SO4 = BaSO4 + 2HCl;
Upon the interaction of 1 mol of barium chloride and 1 mol of sulfuric acid, 1 mol of insoluble barium sulfate is synthesized.
Let’s calculate the chemical amount of the substance, which is contained in 200 grams of 5% sulfuric acid solution.
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;
N H2SO4 = 200 x 0.05 / 98 = 0.102 mol;
The same amount of barium sulfate will be synthesized.
Let’s calculate its weight.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;
m BaSO4 = 233 x 0.102 = 23.77 grams;