Calculate the mass of the precipitate that forms when barium chloride reacts with a solution containing 210 grams of sodium silicate.

univerkov | January 17, 2021 | education

Given:
m in islands (Na2SiO3) = 210 g
To find:
m (BaSiO3)
Decision:
BaCl2 + Na2SiO3 = BaSiO3 + 2NaCl
n (Na2SiO3) = m / M = 210 g / 122 g / mol = 1.72 mol
n (Na2SiO3): n (BaSiO3) = 1: 1
n (BaSiO3) = 1.72 mol
m (BaSiO3) = n * M = 1.72 mol * 213 g / mol = 366.36 g
Answer: 366.36 g

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